在grep的IF语句 [英] grep in IF statement

问题描述

下面的脚本部分读取$每一行下一步。但是，当我尝试在$到grep特定的模式，即MO下一步，显示在标准输出误差

The following script portion read each line in $next. But when I try to grep particular pattern i.e. "MO" in $next, the error is shown on standard output as

的grep：40922 | OPR：没有这样的文件或目录结果
grep的：MO：没有这样的文件或目录结果
grep的：12345 | OPR：没有这样的文件或目录结果
grep的：MO：没有这样的文件或目录结果
grep的：12345 | 12345 | 202 |地方| LMNO：没有这样的文件或目录

grep: 40922|OPR: No such file or directory
grep: MO: No such file or directory
grep: 12345|OPR: No such file or directory
grep: MO: No such file or directory
grep: 12345|12345|202|local|LMNO: No such file or directory

cat /home/scripts/$E1.out | while read next  
do  
i=`echo $next | awk -F"|" '{print($1)}'`
j=`echo $next | awk -F"|" '{print($2)}'`
k=`echo $next | awk -F"|" '{print($3)}'`
l=`echo $next | awk -F"|" '{print($4)}'`
m=`echo $next | awk -F"|" '{print($5)}'`
n=`echo $next | awk -F"|" '{print($6)}'`
o=`echo $next | awk -F"|" '{print($6)}'`  
if grep -q "MO" $next  
then echo "FOUND;" >> /home/scripts/sql.$E1.out  
else echo "NOT FOUND;" >> /home/scripts/sql.$E1.out  
fi  
done  

$ E1.out文件如下：

$E1.out files looks like :

40922 | OPR MO 12345 | OPR MO 12345 | 12345 | 202 |地方| LMNO

40922|OPR MO 12345|OPR MO 12345|12345|202|local|LMNO

推荐答案

您到 <$ C传递参数$ C>的grep ， $下一，被视为文件名进行搜索列表。如果您想该行中搜索字符串，比方说， MO ，那么你需要要么把它放在一个文件并通过该文件作为参数，或管它通过标准输入。

The argument you pass in to grep, $next, is being treated as a list of filenames to search through. If you would like to search within that line for a string, say, MO, then you need to either put it in a file and pass that file in as an argument, or pipe it in via standard input.

下面是一个例子，你可以尝试在命令行上;当然，替换你正在使用的字面意义，我包括说明变量：

Here's an example that you can try out on the command line; of course, substitute the variable that you're using for the literal value that I included to illustrate:

if echo "40922|OPR MO 12345|OPR MO 12345|12345|202|local|LMNO" | grep -q "MO"
  then echo "FOUND"
  else echo "NOT FOUND"
fi

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