如何不产卵2 proceses我跑的nohup为不同的用户？ [英] How do I run nohup as a different user without spawning two proceses?

问题描述

我想NOHUP命令并运行它以不同的用户，但每次我做这两个进程产生了。

I'm trying to nohup a command and run it as a different user, but every time I do this two processes are spawned.

例如：

$ nohup su -s /bin/bash nobody -c "my_command" > outfile.txt &

这绝对my_command以nobody运行，但有一个额外的过程，我不来体现出来想要的：

This definitely runs my_command as nobody, but there's an extra process that I don't want to shown up:

$ ps -Af
.
.
.
root ... su -s /bin/bash nobody my_command
nobody ... my_command

如果我杀了根的过程中，没有人过程仍然生活...但有没有办法不运行在所有的根进程？由于越来越my_command的ID和杀死它是一个比较复杂一点。

And if I kill the root process, the nobody process still lives... but is there a way to not run the root process at all? Since getting the id of my_command and killing it is a bit more complicated.

推荐答案

这可以实现为：

su nobody -c "nohup my_command >/dev/null 2>&1 &"

和写my_command'的pid在PIDFILE：

and to write the pid of 'my_command' in a pidFile:

pidFile=/var/run/myAppName.pid
touch $pidFile
chown nobody:nobody $pidFile
su nobody -c "nohup my_command >/dev/null 2>&1 & echo \$! > '$pidFile'"

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