在获得去年的Bash运行程序的名称 [英] Get name of last run program in Bash

问题描述

我有一个bash脚本，我使用的陷阱命令捕获错误，我希望能够打印的最后一个命令的名称（失败的）

I have a bash script where I trap errors using the trap command, and I would like to be able to print the name of the last command (the one that failed)

#!/bin/bash
function error
{
   # echo program name
}
trap error ERR
 # Some commands ...
/bin/false foo # For testing

我不知道要放什么东西在错误功能。我试图回声$ _ 但如果命令没有变，只有工作。我也试图与 !! 但是这给了我!!：命令未找到。在一个交互式提示符（也bash）的我得到：

I'm not sure what to put in the error function. I tried echo $_ but that only works if the command has no arguments. I also tried with !! but that gives me "!!: command not found". At an interactive prompt (also bash) I get:

$ /bin/false foo
$ !!
/bin/false foo

这似乎是pretty我想太多的东西。为什么会有差别？
是什么让一个脚本里面的previous命令的名称最简单的方法？

which seems to be pretty much what I want. Why the difference? What is the easiest way to get the name of the previous command inside a script?

推荐答案

尝试回声$ BASH_COMMAND 在你的陷阱功能。

从男人庆典：

BASH_COMMAND结果
                该命令正在执行或者即将执行，
                除非壳正在执行的命令为陷阱的结果，
                在这种情况下，它是在该时间执行命令
                陷阱。

BASH_COMMAND
The command currently being executed or about to be executed, unless the shell is executing a command as the result of a trap, in which case it is the command executing at the time of the trap.

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