登录到网站，然后张贴到网页中它 [英] Login to a site and then POST to a page in it

问题描述

我登录到使用三个参数的页面，在那之后我有权发布两个参数来我刚刚登录的站点内的另一页。

I have to login to a page using three parameters, after that I have to POST two parameters to another page inside the site I've just logged in.

到目前为止，我已经有了一个cookie与此：

So far I've got a cookie with this:

curl -c cookie.txt -d "username=username&pwd=pwd&domain=mydomain" http://myurl

...饼干里面我有一个JSESSION ID。
我使用cookie如下：

...inside of the cookie I have a JSESSION id. I use the cookie as follows:

curl -b cookie.txt -d "par=value" http://myurlnumbertwo

问题：

• 甚至张贴到登录URL我在控制台中看到登录页面的HTML code后，这是否意味着登录没有成功？我如何才能找到导致这个错误，也许日志？


• 成功登录我怎么留在登录会话和POST我参数到其他网页后？

编辑：

我终于stran的提示后，这方面的工作，遵循code。

I finally got this working after stran's hint, follows the code.

• POST_DATA包含被张贴，如确切的EN codeD字符串'参数1 =值1＆放大器;参数2 =值2


• ACTION_URL包含哪些形式发布，如 http://stackoverflow.com/users/login 的完整URL

• POST_DATA contains the exact encoded string that was posted, as in 'parameter1=value1&parameter2=value2'
• ACTION_URL contains the full URL to which the form is posted, as in http://stackoverflow.com/users/login

首先，我做了一个

wget --save-cookie cookie.txt --post-data 'POST_DATA' ACTION_URL

使登录并保存的Cookie，随后是：

to make the login and save the cookie, followed by a:

wget --load-cookie cookie.txt --post-data 'POST_DATA' ACTION_URL

，使我所需要的POST，再次感谢你的提示^^

to make the POST I needed, thank you again for the hint ^^

推荐答案

我给wget的一个尝试。有一个 - 保存 - 饼干和 - 负载饼干选项，允许您使用一个Cookie文件。还有处理会话cookie，设施 - 保持会话饼干。请参考wget的手册页了解更多：）

I'd give wget a try. There is a --save-cookies and --load-cookies option that allows you to use a cookie file. There's also a facility for handling session cookies, --keep-session-cookies. Refer to the wget man page for more :)

就个人而言，我有很多更好的运气通过wget的帖子。

Personally, I've had much better luck with post through wget.

GL！

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