在shell脚本整数EX pression预期的错误 [英] Integer expression expected error in shell script

问题描述

我shell脚本，所以我有一个问题一个新手。什么即时做错了这个code？

I'm a newbie to shell scripts so I have a question. What Im doing wrong in this code?

#!/bin/bash
echo " Write in your age: "
read age
if [ "$age" -le "7"] -o [ "$age" -ge " 65" ]
then
echo " You can walk in for free "
elif [ "$age" -gt "7"] -a [ "$age" -lt "65"]
then
echo " You have to pay for ticket "
fi

当我试图打开这个脚本，它要求我为我的年龄，然后它说

When I'm trying to open this script it asks me for my age and then it says

./bilet.sh: line 6: [: 7]: integer expression expected
./bilet.sh: line 9: [: missing `]'

我没有任何想法，我做错了。如果有人能告诉我如何解决它，我会心存感激，对不起我的英文不好，我希望你们能理解我。

I don't have any idea what I'm doing wrong. If someone could tell me how to fix it I would be thankful, sorry for my poor English I hope you guys can understand me.

推荐答案

您可以使用此语法：

#!/bin/bash

echo " Write in your age: "
read age

if [[ "$age" -le 7 || "$age" -ge 65 ]] ; then
    echo " You can walk in for free "
elif [[ "$age" -gt 7 && "$age" -lt 65 ]] ; then
    echo " You have to pay for ticket "
fi

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