巴什 - 我应该怎么闲着，直到我得到的信号？ [英] Bash – How should I idle until I get a signal?

问题描述

我对的launchd运行启动服务器的脚本，然后告诉它的时候的launchd杀死其关闭（这应该是在关机时）正常退出。我的问题：什么是合适的，惯用的方式来告诉脚本空闲直到它得到的信号？如果我只是用一个，而真睡眠-1环，还是有更好的方法来做到这一点？

 ＃！/斌/庆典CD目录名`$ 0`陷阱./serverctl停止一词
./serverctl启动＃等待接收TERM信号。
 

解决方案

一个普通的等是资源密集型的显著不到一个自旋锁，即使在睡眠吧。

I have a script for launchd to run that starts a server, then tells it to exit gracefully when launchd kills it off (which should be at shutdown). My question: what is the appropriate, idiomatic way to tell the script to idle until it gets the signal? Should I just use a while-true-sleep-1 loop, or is there a better way to do this?

#!/bin/bash

cd "`dirname "$0"`"

trap "./serverctl stop" TERM
./serverctl start

# wait to receive TERM signal.

解决方案

A plain wait would be significantly less resource-intensive than a spin lock, even with a sleep in it.

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