虽然Do循环和变量在bash脚本？ [英] While Do loop and variables in a bash script?

问题描述

我是一个PHP程序员做一些bash脚本编程，我不知道如何全局变量都在工作。

欲增加每行的3个变量中提供的文件。然而，当我深究，变量仍设置为0。我如何访问是在WHILE中增加变量DO循环？我只是想呼应出来末..

据我了解我们在kornshell

 ＃！/斌/庆典排版-i I = 0
排版-i T1 = 0
排版-i T2 = 0
SED 1D $ 1 | \\而读字词1字词2 WORD3 word4的word5
做
        I = I + 1
        T1 = T1 + $ word4
        T2 = T2 + $的word5
DONE回声$我
回声$ T1
回声$ T2
退出0
 

解决方案

BASH FAQ条目＃24：我设置变量在一个循环中。为什么他们突然消失循环终止后？或者说，我为什么不能管数据读？

I'm a PHP programmer doing some BASH scripting and I'm not sure how global variables are working.

I want to increment the 3 variables for each line in a supplied file. However, when I get to the bottom, the variables are still set at 0. How do I access the variables that are incremented within the WHILE DO loop? I just want to echo them out at the end..

From what I understand we're in kornshell

#!/bin/bash

typeset -i i=0
typeset -i t1=0
typeset -i t2=0


sed 1d $1 |  \

while read word1 word2 word3 word4 word5 
do
        i=i+1
        t1=t1+$word4
        t2=t2+$word5
done

echo $i
echo $t1
echo $t2


exit 0

解决方案

BASH FAQ entry #24: "I set variables in a loop. Why do they suddenly disappear after the loop terminates? Or, why can't I pipe data to read?"

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