如何停止X code来自shell脚本构建 [英] How to stop Xcode build from shell script

问题描述

我目前的工作与第X code的应用程序，我已经添加了一个运行shell脚本中的构建阶段。

I am currently working on an app in Xcode where I've added a Build Phase that runs a shell script.

该脚本查找从桌面并将其复制到应用程序的资源。如果文件/文件夹不存在，该脚本应取消该应用程序的构建。

The script looks for resources from the Desktop and copies them to the app . If the files/folders don't exist, the script should cancel the build of the app.

我曾尝试各种事物停止构建，如 X codebuild干净，但我不能完全弄清楚。以下是我有：

I have tried various things to stop the build such as xcodebuild clean but I can't quite figure it out. Here is what I have:

if [ -d ~/Desktop/MyFolder ]; then
    cp -r ~/Desktop/MyFolder ${CONFIGURATION_BUILD_DIR}/${UNLOCALIZED_RESOURCES_FOLDER_PATH}/MyFolder
else
    #Stop the build
fi

有没有办法让脚本告诉X code停止建设？如果是这样，我该怎么办呢？

Is there a way to have the script tell Xcode to stop the build? If so, how can I do it?

推荐答案

您需要从脚本返回一个非零退出code：

You need to return a non-zero exit code from the script:

exit 1

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