如何逃脱bash脚本字符串 [英] How to escape strings in bash script

问题描述

我正在调用MySQL的bash脚本。密码北京时间无法正常传输，我想我必须逃避一些特殊的字符，如哈希或美元符号？

＃！/斌/庆典USER = myuser的
PASS =＃$为mypass＃...调用的MySQL

解决方案

使用...已经是做了正确的事情，但 $ 需要转义（ \\ $ ），如果它后面没有无效字。然而，你还需要确保始终有引号中的变量，以及，如：

  somecommand -p$ PASS
 

I am running a bash script that calls mysql. The password ist not correctly transmitted, I guess I have to escape some special chars, like the hash or the dollar sign?

#!/bin/bash

USER=myuser
PASS="#mypass$"

# ... call mysql

解决方案

Using "..." is already the correct thing to do, but the $ needs to be escaped (\$) if it isn't followed by an "invalid" character. However you also need to make sure to always have the variable in quotation marks as well, as in:

somecommand -p "$PASS"

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