如何计算行之后与字线在哪里字词2 -bash [英] How to count lines with word after line where is word2 -bash

问题描述

我有一个大的文本文件，其中一些行包含单词DataMeetingIs11其中，以下行包含单词完成。我的任务是计算所有这样的行。比如我想算如下：

I have a big text file where some lines contain the word "DataMeetingIs11" where the following line contains the word "done". My task is to count all such lines. For example I want to count the following:

......DataMeetingIs11.....
....done..................

但不是以下内容：

but not the following:

 ......DataMeetingIs11.....
 ..........................

我尝试使用下一个命令：

I tried using the next command:

grep -A 1 DataMeetingIs11 file| grep -c done 

但它没有工作。你能帮帮我吗？

but it didn't work. Can you please help me?

修改

如何计算不做字线？

推荐答案

您可以用awk来代替：

You can use awk instead:

awk '/DataMeetingIs11/ {a++; p=NR} /done/ && NR==(p+1) {c++} 
     END{print "Without done:", (a-c) ", With done:", c}' file
Without done: 1, With done: 2

说明：

/DataMeetingIs11/    # when input line matches literal "DataMeetingIs11"
{a++; p=NR}          # store current line # NR into variable p and increment a
/done/ && NR==(p+1)  # when line matches "done" and when 
                     # current line # is p+1 (next line)
{c++}                # increment a counter c
END{print (a-c), c}  # print counts the end

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