脚本列出所有的例外情况及其发生的数 [英] A script to list all the exceptions and their number of occurrence

问题描述

我有codeD可以分析一个文件，并返回不同结果的分析： GOOD ， BAD ，意外异常：后面是不同的异常...我的生成文件运行此分析仪上的一组文件之一接着一个，并把整个结果在一个文件中 output.txt的。因此， output.txt的看起来如下：

I have coded an analyzer which analyzes a file, and returns different results: GOOD, BAD, Unexpected exception : which is followed by different exceptions... My makefile runs this analyzer on a set of files one by one, and puts the whole result in one file output.txt. So the output.txt looks like as follows:

file "f1.txt"
...
GOOD
file "f2.txt"
...
Unexpected exception : exception1
...
Unexpected exception : exception2
...

现在我想编写一个shell脚本摘要，总结 output.txt的，尤其是名单是什么例外凸起和它们发生的次数。它应该喜欢就好：

Now I would like to write a shell script summary which summarizes output.txt, especially lists what exceptions are raised and their number of occurrence. It should like like:

exception1 : 9
exception2 : 15
...

例外的顺序没有任何意义，（当然，如果是发生数进行排序，这将是更好的）...

The order of the exceptions has no importance, (well, if it is sorted by the number of the occurrence, it would be better)...

我知道 grep的意外的异常output.txt的|厕所-l 将返回所有的异常出现的次数，但我确实需要知道募集每个异常的发生...

I know grep "Unexpected exception" output.txt | wc -l will return the number of occurrence of all the exceptions, but I do need to know the occurrence for each exception raised...

有谁知道如何写这个摘要脚本？

Does anyone know how to write this summary script?

推荐答案

您可以用awk：

awk -F ' : ' '$1=="Unexpected exception"{a[$2]++} END{for (i in a) print i,a[i]}' output.txt

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