在bash字符串连接空间，并把周围的报价 [英] String Concatenation in bash with space and putting quote around
问题描述
我在我的<一个很好的反应href=\"http://stackoverflow.com/questions/37426985/concatenating-remaining-arguments-beyond-the-first-n-in-bash\">last问题。当时的想法是要处理N多的命令行输入，保存前9个变量，使一个字符串10起。
I got a very good response in my last question. The idea was to process N number of inputs from command line, save first 9 to variables and make a string with 10 to onward.
我觉得这是最简单的解决方案。
I found this to be the easiest solution.
var1="$1"
var2="$2"
var3="$3"
var4="public"
var5="$5"
var6="''"
var7="$7"
var8="$8"
var9="$9"
var10="$(shift 9; IFS=""; echo "$*")"
echo snmptrap $var1 $var2 $var3 $var4 $var5 $var6 $var7 $var8 $var9 "$var10"
snmptrap $var1 $var2 $var3 $var4 $var5 $var6 $var7 $var8 $var9 "$var10"
输出看起来像这样...
The output looks like this...
./snmptas -v 2c -c "" 9.48.85.57 "" 1.3.6.1.4.1.2.6.201.3 s s ABC DDEF EFFF
snmptrap -v 2c -c public 9.48.85.57 '' 1.3.6.1.4.1.2.6.201.3 s s ABCDDEFEFFF
不过，我以这种形式要$ var10
But I wanted $var10 in this form
ABC DDEF EFFF。
"ABC DDEF EFFF".
这需要改变。它采取的空间了。
This needs to changed. It's taking the spaces off.
var10="$(shift 9; IFS=""; echo "$*")"
我怎样才能让var10 =ABC DDEF EFFF？
How can I make var10 = "ABC DDEF EFFF"?
感谢
推荐答案
一个子shell回声是不是真的适合那里。更好的是这样的：
A subshell with echo is not really appropriate there. Better this way:
shift 9
var10="$*"
如果你想周围的报价为价值的一部分，然后更改最后一行：
If you want quotes around that as part of the value, then change the last line to:
var10=\""$*"\"
无关到，我想知道，如果你的治疗 var6 做你的本意。我怀疑，这将是更接近你真正想要的结果：
Unrelated to that, I'm wondering if your treatment for var6 does what you intended. I suspect that this will be closer to what you really intended:
snmptrap $var1 $var2 $var3 $var4 $var5 '' $var7 $var8 $var9 "$var10"
或者这样：
var6=
snmptrap $var1 $var2 $var3 $var4 $var5 "$var6" $var7 $var8 $var9 "$var10"
但是，如果我的猜测是错误的，你原来的治疗如预期那么没关系，忽略了这些言论。
But if my guess is wrong and your original treatment is working as intended then never mind, ignore these remarks.
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