BASH：所有文件和目录复制到另一个目录在同一个父目录 [英] BASH: Copy all files and directories into another directory in the same parent directory

问题描述

我试图做一个简单的脚本，复制我所有的 $ HOME 到 $ HOME另一个文件夹名为备份/ 。这包括所有隐藏文件和文件夹，不包括备份/ 本身。我现在所拥有的用于复制的部分如下：

I'm trying to make a simple script that copies all of my $HOME into another folder in $HOME called Backup/. This includes all hidden files and folders, and excludes Backup/ itself. What I have right now for the copying part is the following:

shopt -s dotglob

for file in $HOME/*
do
    cp -r $file $HOME/Backup/
done

猛砸告诉我，它无法复制备份/ 到自身。然而，当我检查的内容 $ HOME /备份/ 我看到 $ HOME /备份/备份/ 存在。

Bash tells me that it cannot copy Backup/ into itself. However, when I check the contents of $HOME/Backup/ I see that $HOME/Backup/Backup/ exists.

备份/ 的本身副本是没用的。我怎样才能在bash的所有文件夹复制到除备份/ 。我试着用 extglob ，并使用 CP -r $ HOME /！（备份）/ 但它没有拷贝过来隐藏的文件，我需要的。

The copy of Backup/ in itself is useless. How can I get bash to copy over all the folders except Backup/. I tried using extglob and using cp -r $HOME/!(Backup)/ but it didn't copy over the hidden files that I need.

推荐答案

我同意使用的rsync 将是一个更好的解决方案，但有一个简单的方法来跳过在目录庆典：

I agree that using rsync would be a better solution, but there is an easy way to skip a directory in bash:

for file in "$HOME/"*
do
    [[ $file = $HOME/Backup ]] && continue
    cp -r "$file" "$HOME/Backup/"
done

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