在bash使用正则表达式在一个字符串多个匹配 [英] Multiple matches in a string using regex in bash

问题描述

一直在寻找与正则表达式bash的一些更高级的正则表达式的信息，并没有发现它的信息。

Been looking for some more advanced regex info on regex with bash and have not found much information on it.

这里的理念，用一个简单的字符串：

Here's the concept, with a simple string:

myString="DO-BATCH BATCH-DO"

if [[ $myString =~ ([[:alpha:]]*)-([[:alpha:]]*) ]]; then
 echo ${BASH_REMATCH[1]} #first perens
 echo ${BASH_REMATCH[2]} #second perens
 echo ${BASH_REMATCH[0]} #full match
fi

outputs:
BATCH
DO
DO-BATCH

那么细它的第一场比赛（批次DO），但我怎么拉的第二场比赛（DO-批）？我只是一片空白这里找不到bash的正则表达式多的信息。

So fine it does the first match (BATCH-DO) but how do I pull a second match (DO-BATCH)? I'm just drawing a blank here and can not find much info on bash regex.

推荐答案

确定这样一种方式我这样做是为了把它放在一个for循环：

OK so one way I did this is to put it in a for loop:

myString="DO-BATCH BATCH-DO"
for aString in ${myString[@]}; do
    if [[ ${aString} =~ ([[:alpha:]]*)-([[:alpha:]]*) ]]; then
     echo ${BASH_REMATCH[1]} #first perens
     echo ${BASH_REMATCH[2]} #second perens
     echo ${BASH_REMATCH[0]} #full match
    fi
done

which outputs:
DO
BATCH
DO-BATCH
BATCH
DO
BATCH-DO

这工作，但那种我希望如果可能的话把它拉一切从一个正则表达式。

Which works but I kind of was hoping to pull it all from one regex if possible.

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