我怎么能等到指定的＆QUOT; xterm的＆QUOT;完了吗？ [英] How can I wait until specified "xterm" finished?

问题描述

在我的C-shell文件，我不喜欢的东西：

In my c-shell file, I did something like:

的xterm -e源xxxx0＆放​​大器;

xterm -e "source xxxx0" &

的xterm -e源xxxx1与＆amp;

xterm -e "source xxxx1" &

等

code ....

code....

它工作正常，经过code等待将执行两个的xterm结束后。

It works fine that code after "wait" will be executed after the two xterm finished.

不过，这也给了问题。如果我有一些PS打开，就像打开geditn一个txt文件，或者我有开放的日食，它会因为等待正在等待完成所有作业挂在那里。

But it also gives problem. If I have some ps open, like an txt file opened by geditn, or I have an eclipse open, it will hung there since "wait" is waiting for all jobs to be finished.

那么，如何才能让等待等待只为这两个xterm的工作。

So how can I let "wait" only wait for those two xterm jobs.

或在另一个词，我想这两个xterm的同时运行。之后他们都做了，code可以继续。我该怎样做呢？

Or in another word, I want those two "xterm" run concurrently. And after they both done, the code can be continued. How shall I do that?

非常感谢你。

推荐答案

告诉等进程ID应该等待：

Tell wait the process ids it should wait for:

xterm ... &
pid1=$!

xterm ... &
pid2=$!

wait $pid1 $pid2

这是假设你使用的shell，其中等支持多种参数（bash中，zsh中，...）。如果你使用的是sh便携性，那么你必须做两等待：

That's assuming you use a shell where wait supports multiple arguments (bash,zsh, ...). If you use sh for portability, then you have to do two waits:

wait $pid1
wait $pid2

这将等待直到双方完成。如果说之前的第二个结束的第一个，等待将立即返回。

This will wait untill both are finished. If the second finishes before the first, the wait will immediately return.

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