如果猛砸 - ＆GT;那么如果 - ＆GT;否则跳到第一ELIF [英] Bash if -> then if -> else skip to first elif

问题描述

code：

if [cond1]
   then if [cond2]
        then ...
        else skip to elif
   fi

elif[cond3]
   then ...
fi

如果第二个条件不匹配跳到ELIF。

If second condition doesn't match skip to elif.

推荐答案

请注意，在低于code， ELIF QUUX ... 是任何一个占位符 ELIF 你得了之后 ELIF cond3 。

Note that in the below code, elif quux... is a placeholder for whatever elifs you have after elif cond3.

的（也就是说，你希望在你跳过执行其code，即使 cond3 是假的。）的

(That is, you want to execute its code when you skip, even if cond3 is false.)

正如@ code4me建议，你可以使用一个功能：

As suggested by @code4me, you could use a function:

foo() { 
  # do work
}

if cond1; then
  if cond2; then
    ...
  else
    foo
  fi
elif cond3; then
  foo
elif quux...

这也是@ fedorqui的建议如下：

This is also where @fedorqui's suggestion works:

if cond1 && cond2; then
  ...
elif cond3; then
  # do work
elif quux...

如果您的不的需要测试 cond3 上跳过

逻辑变得更难理解。

If you do need to test cond3 on skipping

The logic gets harder to follow.

foo() {
  # Note the condition is tested here now
  if cond3; then
    # do work
  fi
}

if cond1; then
  if cond2; then
    ...
  else
    foo
  fi
else
  # This code is carefully constructed to ensure that subsequent elifs
  # behave correctly
  if ! foo; then
    # Place the other elifs here
    if quux...

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