Python的POPEN无法打开的CentOS /红帽的bash shell [英] Python Popen can't open bash shell in CentOS/Red Hat

问题描述

我无法打开CentOS的是bash shell与Python 2.7，我能够在Python 2.6.6的Debian这样做。发生了什么变化？

I can't open a bash shell in CentOS with python 2.7, I'm able to do so in python 2.6.6 Debian. What has changed?

我试过一个简单的bash进程替换：

I tried a simple bash process substitution:

from subprocess import Popen
cmd="""cat <<'EOF'
this is
test $unchanged
EOF
"""
Popen('cat <(%s)' % cmd, shell=True, executable='/bin/bash')

在Debian的这部作品，在CentOS的它不：

In Debian this works, in CentOS it doesn't:

/bin/sh: -c: line 0: syntax error near unexpected token `('
/bin/sh: -c: line 0: `cat <(cat <<'EOF''

的区别是：

• 的Debian ：Python的2.6.6， / bin / sh的由破折号提供


• CenOS （红帽）：Python的2.7， / bin / sh的由庆典提供

• Debian: Python 2.6.6, /bin/sh is provided by dash.
• CenOS (Red Hat): Python 2.7, /bin/sh is provided by bash

因此​​，在CentOS的在 =可执行文件/ bin中/庆典不是的荣幸的。
我缺少的东西吗？

So in CentOS the executable=/bin/bash is not being honored at all. Am I missing something?

推荐答案

如果你写的参数/斌/ bash的？

What if you write /bin/bash in arguments?

Popen(['/bin/bash', '-c', 'cat <(%s)' % cmd])

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