从给出/ L参数批量输出日期的列表 [英] Batch to output a list of dates from given for /L parameter

问题描述

请考虑以下codeS：

Please consider the following codes:

@echo off
setlocal enabledelayedexpansion

FOR /L %%G IN (0,1,19) DO (
set /a "Dday=%_day%+%%G"

if %mth% equ sml (
    if !Dday! gtr 30 (
        set "_day=1"
        set /a "_month+=1"          
    )
    if !_month! gtr 12 (
        set "_month=1"
        set /a "_year+=1"
    )

) else (
    if %mth% equ big (
        if !Dday! gtr 31 (
            set "_day=1"
            set /a "_month+=1"
        ) 
        if !_month! gtr 12 (
            set "_month=1"
            set /a "_year+=1"
        )
    )
)

echo !Dday!/!_month!/!_year!.txt
)

考虑下面的日期：20/04/2016

Consider the following date: 20/04/2016

_day = 20 ; _month = 04 ; _year = 2016年; 总分= SML ;

和我的输出是这样的：

它增加了30天，而不是改变它为1。我可以知道我做了什么错？请指教。谢谢

It increases the day from 30 instead of changing it to 1. Can I know what have I done wrong? Please advise. Thanks

推荐答案

有此脚本中两个问题。首先作为@SomethignDark指出的那样，你需要使用！_天！，而不是％_一天％。

There are two problems in this script. First as @SomethignDark pointed out, you need to use !_day! instead of %_day%.

二，当 DDAY 大于30， %%摹是12.所以，你的前pression的！_天！+ %%摹将是13而不是1。

Second when Dday is greater than 30, %%G is 12. So you expression of !_day!+%%G will be 13 instead of 1.

所以，你需要像

...
FOR /L %%G IN (0,1,19) DO (

set /a "Dday=!_day!+%%G"

if !_day! equ 1 set /a "Dday=!_day!+%%G-12"
...

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