使用批处理计算的特定文件夹中的文件数 [英] Using batch to count the number of specific files in folder

问题描述

我有一大堆的文件夹他们的名字都像a1.txt，a6.txt，a8.txt，在文件的..我需要算来我试过这个批处理文件，但它不承认*作为方法来解释所有数字和不返回正确的答案。

I have a bunch of files in a folder that their names are like a1.txt, a6.txt, a8.txt,..and I need to count them I tried this batch file but it does not recognize * as a way to account for all numbers and does not return the correct answer.

set /a count=0
for /F "tokens=* delims= " %%i in ('dir/s/b/a-d "C:\Users\xyz\desktop\Project\a.*"') do (set /a count=count+1) 

你能看见什么，我做错了什么？感谢您的帮助提前。

Can you see what I am doing wrong? Thanks for your help in advance.

推荐答案

有类似的问题面前，我preFER使用的伎俩，我从雷蒙德陈了解到，至极是的使用找到作为替代 WC -l <​​/ code> 。

Faced with a similiar problem, I prefer to use a trick I learned from Raymond Chen, wich is to use find as a replacement for wc -l.

所以下面scrit设置批次变量计数来匹配 patttern 的文件的数量。就像你的原始脚本，目录被排除在计数。

So the following scrit sets the batch variable count to the number of files that match patttern. Like your original script, directories are excluded from the count.

@echo off

setlocal

set count=0
set pattern=a?.txt

use dir /b %pattern% ^| find /c /v ""

for /f %%i in ('dir /b /a-d %pattern_you_are_looking_for% ^| find /c /v ""') do @call set count=%%i

echo %count%

endlocal

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