使用Python计算并打印子文件夹中的文件数 [英] Count and print number of files in subfolders using Python

问题描述

我的文件夹结构如下

文件夹A

文件夹B1

文件夹B2

....

文件夹Bn

My folder structure is as follows
Folder A
Folder B1
Folder B2
....
Folder Bn

如何计算每个文件夹中的文件数量（文件夹B1 - 文件夹Bn），检查文件数量是否更大

How can I count the number of files in each of the folders (Folder B1 - Folder Bn), check if the number of files is larger than a given limit and print the folder name and number of files in it on the screen?

像这样：

文件太多的文件夹：

文件夹B3 101

文件夹B7 256

Like this:
Folders with too many files:
Folder B3 101
Folder B7 256

这是我到目前为止的尝试。它通过我的每个文件夹B1中的每个子文件夹等。我只需要文件计数在一个级别。

Here's what I've tried so far. It goes through every subfolder in each of my Folder B1 etc. I just need file count in one level.

import os, sys ,csv
path = '/Folder A/'

outwriter = csv.writer(open("numFiles.csv", 'w')

dir_count = []

for root, dirs, files in os.walk(path):
    for d in dirs:
        a = str(d)
        count = 0
        for fi in files:
            count += 1
        y = (a, count)
        dir_count.append(y)

    for i in dir_count:
        outwriter.writerow(i)

然后我刚刚打印了numFiles.csv。我想这样做。
提前感谢！

And then I just printed numFiles.csv. Not quite how I'd like to do it. Thanks in advance!

推荐答案

由于都包含在单个文件夹中，您只需要搜索该目录：

As the are all contained in that single folder, you only need to search that directory:

import os
path = '/Folder A/'
mn = 20
folders = ([name for name in os.listdir(path)
            if os.path.isdir(os.path.join(path, name)) and name.startswith("B")]) # get all directories 
for folder in folders:
    contents = os.listdir(os.path.join(path,folder)) # get list of contents
    if len(contents) > mn: # if greater than the limit, print folder and number of contents
        print(folder,len(contents)

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