获取与BeautifulSoup文件DOCTYPE [英] Get document DOCTYPE with BeautifulSoup

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本文介绍了获取与BeautifulSoup文件DOCTYPE的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我刚刚开始 scrapy 用的 BeautifulSoup ,我想知道如果我失去了一些东西很明显,但我似乎无法弄清楚如何摆脱由此产生的汤对象返回的HTML文档的文档类型。

I've just started tinkering with scrapy in conjunction with BeautifulSoup and I'm wondering if I'm missing something very obvious but I can't seem to figure out how to get the doctype of a returned html document from the resulting soup object.

由于fllowing HTML:

Given the fllowing html:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html lang="en"> 
<head> 
<meta charset=utf-8 />
<meta name="viewport" content="width=620" />
<title>HTML5 Demos and Examples</title> 
<link rel="stylesheet" href="/css/html5demos.css" type="text/css" /> 
<script src="js/h5utils.js"></script> 
</head> 
<body>
<p id="firstpara" align="center">This is paragraph <b>one</b>
<p id="secondpara" align="blah">This is paragraph <b>two</b>.
</html>

谁能告诉我,如果有使用BeautifulSoup从中提取DOCTYPE声明的一种方式?

Can anyone tell me if there's a way of extracting the declared doctype from it using BeautifulSoup?

干杯。

推荐答案

美丽的汤4有DOCTYPE声明一个类,所以你可以用它来在顶级提取所有的声明(虽然你无疑期待一个或没有!)

Beautiful Soup 4 has a class for DOCTYPE declarations, so you can use that to extract all the declarations at top level (though you're no doubt expecting one or none!)

def doctype(soup):
    items = [item for item in soup.contents if isinstance(item, bs4.Doctype)]
    return items[0] if items else None

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