如何打开一个二进制字符串转换成float或double？ [英] How do I turn a binary string into a float or double?

问题描述

在这个问题，比尔蜥蜴问如何显示一个浮动或双的二进制重新presentation

我想知道的是，给予适当长度的二进制字符串，我怎么能执行相反操作（C＃）？换句话说，我怎么把一个二进制字符串转换成float或double？

作为一个方面说明，还有这会不会导致一个有效的float或double任何位串？

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编辑：通过二进制字符串我的意思是0和1的字符串

所以，我的投入将是这样一个字符串：

  01010101010101010101010101010101
 

和我的输出应为一个浮点数。 （或者，如果有64比特串中，一个双）

解决方案

 字符串BSTR =01010101010101010101010101010101;
长V = 0;
对（INT I = bstr.Length  -  1; I＆GT; = 0;我 - ）ν=（V＆所述;＆所述; 1）+（BSTR [I]  - '0'）;
双D = BitConverter.ToDouble（BitConverter.GetBytes（v）中，0）;
// D = 1.41466386031414E-314
 

In this question, Bill The Lizard asks how to display the binary representation of a float or double.

What I'd like to know is, given a binary string of the appropriate length, how could I perform the reverse operation (in C#)? In other words, how do I turn a binary string into a float or double?

As a side note, are there any bit strings which would not result in a valid float or double?

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EDIT: By binary string I mean a string of 0s and 1s.

So, my input will be a string like this:

01010101010101010101010101010101

and my output should be a floating point number. (Or, if there were 64 bits in the string, a double.)

解决方案

string bstr = "01010101010101010101010101010101";
long v = 0;
for (int i = bstr.Length - 1; i >= 0; i--) v = (v << 1) + (bstr[i] - '0');
double d = BitConverter.ToDouble(BitConverter.GetBytes(v), 0);
// d = 1.41466386031414E-314

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