将double转换成字符串C ++？ [英] Convert double to string C++?

问题描述

可能重复：

如何将双精度转换为C ++中的字符串？

我想结合一个字符串和一个double，g ++抛出这个错误：

I want to combine a string and a double and g++ is throwing this error:

main.cpp：In函数'int main（）'：

main.cpp：40：错误：类型为const char [2]和double的无效操作数到二进制运算符+

main.cpp: In function ‘int main()’:
main.cpp:40: error: invalid operands of types ‘const char [2]’ and ‘double’ to binary ‘operator+’

以下是代码中的错误代码：

Here is the line of code which it is throwing the error on:

storedCorrect[count] = "("+c1+","+c2+")";

storedCorrect []是一个字符串数组，并且c1和c2均为双精度。有没有办法将c1和c2转换成字符串来允许我的程序正确编译？

storedCorrect[] is a string array, and c1 and c2 are both doubles. Is there a way to convert c1 and c2 to strings to allow my program to compile correctly?

推荐答案

你不能这样做直。有很多方法可以实现：

You can't do it directly. There are a number of ways to do it:

1. 使用 std :: stringstream ：

std::ostringstream s;
s << "(" << c1 << ", " << c2 << ")";
storedCorrect[count] = s.str()

使用 boost :: lexical_cast ：

storedCorrect[count] = "(" + boost::lexical_cast<std::string>(c1) + ", " + boost::lexical_cast<std::string>(c2) + ")";

使用 std :: snprintf ：

char buffer[256];  // make sure this is big enough!!!
snprintf(buffer, sizeof(buffer), "(%g, %g)", c1, c2);
storedCorrect[count] = buffer;

还有其他一些方法，使用各种双字符串转换功能，但这些是您将看到完成的主要方式。

There are a number of other ways, using various double-to-string conversion functions, but these are the main ways you'll see it done.

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