将字符串转换为二进制[考试] [英] Converting a string to binary [Java]

问题描述

让我们说我有以下字符串：

Let's say I have the following string:

String s = "Hello, stackoverflow"

我将如何将其转换成二进制数（0和1）？这里的窍门：我不允许使​​用内置方法的转换。它必须在数学上进行。我不知道从哪里开始。任何人都可以点我在正确的方向？

How would I convert that into a binary number (0s and 1s)? Here's the trick: I'm not allowed to use built-in methods for the conversion. It has to be done mathematically. I have no idea where to begin. Can anyone point me in the right direction?

编辑1：我已经看到了这个的问题和人民使用的getBytes（串）建议，字符集UTF-8和Integer.toBinaryString。我不能使用任何这些方法进行转换。我还没有听说过36基无论是。

Edit 1: I've seen this question and people suggested using getBytes(string), charset UTF-8, and Integer.toBinaryString. I'm not allowed to use any of these methods for conversion. I haven't heard of 36-base either.

推荐答案

首先获得使用 getByte（）在函数然后使用整数字节格式字符串。 toBinaryString（字节）功能。 ＆安培;完蛋了。

First get bytes form string using getByte() function then use Integer.toBinaryString(byte) function. & thats it.

请注意：〜确保 Integer.toBinaryString（字节）接受INT（或在这种情况下，字节不是全部。）所以你必须按字节通过字节（可能。为循环。）

NOTE:~ Make sure Integer.toBinaryString(byte) accepts int(or in this case byte not all.) so you have to pass byte by byte.(may be for loop.)

编辑：〜
你可以做的是焦炭和放大器解析字符串字符;每个烧焦您可以用得到的ASCII值。

Edited :~ what you can do is parse string char by char & for each char you can get ascii value using.

int tempChar = (int)ch;

然后simpley使用。

Then simpley use this.

Integer.toString(tempChar,2);

试试这个。

string finalString = "";
for(int i = 0;i<myStr.length;i++){
    int tempChar = (int)ch;
    finalString = finalString + Integer.toString(tempChar,2);//& this is not allowed then now only you need to create function for integer to binary conversion.
}
System.out.println("Your byte String is"+finalString);

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