将二进制字符串转换为ASCII字符串(C ++) [英] Convert a string of binary into an ASCII string (C++)

问题描述

我有一个包含32位二进制数的字符串变量.将二进制表示的这4个字符(8位为1个字符)转换回其ASCII字符的最佳方法是什么?

I have a string variable containing 32 bits of binary. What would be the best way to convert these 4 characters (8 bits is one character) represented by the binary back into their ASCII characters?

例如，一个变量包含"01110100011001010110111001101110100"，应将其转换回字符串"test".

For example, a variable contains "01110100011001010111001101110100" which should be converted back into the string "test".

推荐答案

如果您使用的是C ++ 11，则为另一种选择:

An alternative if you're using C++11:

#include <iostream>
#include <string>
#include <sstream>
#include <bitset>

int main()
{
    std::string data = "01110100011001010111001101110100";
    std::stringstream sstream(data);
    std::string output;
    while(sstream.good())
    {
        std::bitset<8> bits;
        sstream >> bits;
        char c = char(bits.to_ulong());
        output += c;
    }

    std::cout << output;

   return 0;
}

请注意，位集是C ++ 11的一部分.

Note that bitset is part of C++11.

还请注意，如果数据格式不正确，当sstream.good()返回false时，结果将被静默截断.

Also note that if data is not well formed, the result will be silently truncated when sstream.good() returns false.

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