文本菜单命令绑定到家长和自我 [英] ContextMenu Command Binding to parent and to self
本文介绍了文本菜单命令绑定到家长和自我的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我想在具有多个命令绑定一个DataGrid创建一个文本菜单。一些已被绑定到本地视图模型（即，行的视图模型）和一些父母视图模型
我至今没有运气下面其他的解决方案。我只得到子命令来执行。
MainViewModel
公共类MainViewModel：ViewModelBase
{
公众的ObservableCollection＆LT; SubViewModel＆GT;项目{搞定;私人集; } 公共MainViewModel（）
{ 项目=新的ObservableCollection＆LT; SubViewModel＆GT;（）; Items.Add（新SubViewModel（））;
Items.Add（新SubViewModel（））;
} 私人RelayCommand _mainCommand; 公众的ICommand MainCommand
{
得到
{
如果（_mainCommand == NULL）
{
_mainCommand =新RelayCommand（
（）=＆GT;
{
的Debug.WriteLine（MAINCOMMAND实行了）;
}
）;
}
返回_mainCommand;
}
}
}
SubViewModel
公共类SubViewModel：ViewModelBase
{
私人RelayCommand _subCommand; 公众的ICommand子
{
得到
{
如果（_subCommand == NULL）
{
_subCommand =新RelayCommand（
（）=＆GT;
{
的Debug.WriteLine（SUBCOMMAND EXECTUED）;
}
）;
}
返回_subCommand;
}
}
}
主窗口
＆LT;窗口x：类=WpfApplication4.MainWindow
的xmlns =http://schemas.microsoft.com/winfx/2006/xaml/$p$psentation
的xmlns：X =http://schemas.microsoft.com/winfx/2006/xaml
标题=主窗口
WIDTH =525
HEIGHT =350
的DataContext ={绑定源= {静态资源定位符}，
路径=主}＆GT;
＆LT;网格和GT;
＆LT;数据网格的ItemsSource ={绑定表项}＆GT; ＆LT; DataGrid.RowStyle＆GT;
＆LT;风格的TargetType ={X：类型DataGridRow}＆GT;
＆LT; setter属性=文本菜单＆GT;
＆LT; Setter.Value＆GT;
＆LT;文本菜单的DataContext ={结合PlacementTarget.DataContext，的RelativeSource = {自我的RelativeSource}}＆GT;
＆LT;菜单项命令={结合DataContext.MainCommand，的RelativeSource = {的RelativeSource模式= FindAncestor，AncestorType = {X：输入文本菜单}}}标题=主/＆GT;
＆LT;菜单项命令={结合}子标题=亚健康/＆GT;
＆LT; /文本菜单＆GT;
＆LT; /Setter.Value>
＆LT; /二传手＆GT;
＆LT; /样式和GT;
＆LT; /DataGrid.RowStyle> ＆LT; / DataGrid的＆GT;
＆LT; /网格和GT;
＆LT; /窗GT;
解决方案
我已经找到一种方法，但我不认为这是太高雅了，也许有一个更好的办法，但这种将工作：
＆LT;窗口x：类=WpfApplication4.MainWindow
的xmlns =http://schemas.microsoft.com/winfx/2006/xaml/$p$psentation
的xmlns：X =http://schemas.microsoft.com/winfx/2006/xaml
标题=主窗口
WIDTH =525
HEIGHT =350
的DataContext ={绑定源= {静态资源定位符}，
路径=主}＆GT;
＆LT;电网X：名称=网格＆GT;
＆LT; DataGrid的X：名称=DataGrid中的ItemsSource ={绑定表项}＆GT; ＆LT; DataGrid.RowStyle＆GT;
＆LT;风格的TargetType ={X：类型DataGridRow}＆GT; ＆LT; setter属性=文本菜单＆GT;
＆LT; Setter.Value＆GT;
＆LT;＆文本菜单GT;
＆LT;菜单项命令={绑定路径= PlacementTarget.Tag.MainCommand，的RelativeSource = {的RelativeSource模式= FindAncestor，AncestorType = {X：输入文本菜单}}}标题=主/＆GT;
＆LT;菜单项命令={结合}子标题=亚健康/＆GT;
＆LT; /文本菜单＆GT;
＆LT; /Setter.Value>
＆LT; /二传手＆GT; ＆LT; setter属性=变量VALUE ={绑定的RelativeSource = {的RelativeSource模式= FindAncestor，AncestorType = {X：类型的DataGrid}}，路径=的DataContext}/＆GT;
＆LT; /样式和GT;
＆LT; /DataGrid.RowStyle> ＆LT; / DataGrid的＆GT;
＆LT; /网格和GT;
＆LT; /窗GT;
I am trying to create a ContextMenu on a DataGrid with multiple Command Bindings. Some have to be bound to the local ViewModel (i.e. the ViewModel of the Row) and some to the parents ViewModel.
I had no luck so far following other solutions. I only get the SubCommand to execute.
MainViewModel
public class MainViewModel : ViewModelBase
{
public ObservableCollection<SubViewModel> Items { get; private set; }
public MainViewModel()
{
Items = new ObservableCollection<SubViewModel>();
Items.Add(new SubViewModel());
Items.Add(new SubViewModel());
}
private RelayCommand _mainCommand;
public ICommand MainCommand
{
get
{
if (_mainCommand == null)
{
_mainCommand = new RelayCommand(
() =>
{
Debug.WriteLine("MAINCOMMAND EXECUTED");
}
);
}
return _mainCommand;
}
}
}
SubViewModel
public class SubViewModel : ViewModelBase
{
private RelayCommand _subCommand;
public ICommand SubCommand
{
get
{
if (_subCommand == null)
{
_subCommand = new RelayCommand(
() =>
{
Debug.WriteLine("SUBCOMMAND EXECTUED");
}
);
}
return _subCommand;
}
}
}
MainWindow
<Window x:Class="WpfApplication4.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow"
Width="525"
Height="350"
DataContext="{Binding Source={StaticResource Locator},
Path=Main}">
<Grid>
<DataGrid ItemsSource="{Binding Items}">
<DataGrid.RowStyle>
<Style TargetType="{x:Type DataGridRow}">
<Setter Property="ContextMenu">
<Setter.Value>
<ContextMenu DataContext="{Binding PlacementTarget.DataContext, RelativeSource={RelativeSource Self}}">
<MenuItem Command="{Binding DataContext.MainCommand, RelativeSource={RelativeSource Mode=FindAncestor, AncestorType={x:Type ContextMenu}}}" Header="Main" />
<MenuItem Command="{Binding SubCommand}" Header="Sub" />
</ContextMenu>
</Setter.Value>
</Setter>
</Style>
</DataGrid.RowStyle>
</DataGrid>
</Grid>
</Window>
解决方案
I have found a way, but I don't think it is too elegant, maybe there is a better way, but this will work:
<Window x:Class="WpfApplication4.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow"
Width="525"
Height="350"
DataContext="{Binding Source={StaticResource Locator},
Path=Main}">
<Grid x:Name="Grid">
<DataGrid x:Name="DataGrid" ItemsSource="{Binding Items}">
<DataGrid.RowStyle>
<Style TargetType="{x:Type DataGridRow}">
<Setter Property="ContextMenu">
<Setter.Value>
<ContextMenu>
<MenuItem Command="{Binding Path=PlacementTarget.Tag.MainCommand, RelativeSource={RelativeSource Mode=FindAncestor, AncestorType={x:Type ContextMenu}}}" Header="Main" />
<MenuItem Command="{Binding SubCommand}" Header="Sub" />
</ContextMenu>
</Setter.Value>
</Setter>
<Setter Property="Tag" Value="{Binding RelativeSource={RelativeSource Mode=FindAncestor, AncestorType={x:Type DataGrid}}, Path=DataContext}" />
</Style>
</DataGrid.RowStyle>
</DataGrid>
</Grid>
</Window>
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