获取CMake的在项目执行的目标建立一个库之前 [英] Get CMake to execute a target in project before building a library

问题描述

我使用的CMake来构建我的C ++项目，它有多个可执行文件和库（同一项目的一部分）。所有工作正常，但我的可执行文件之一是code发生器，产生一些库类的。我已经得到了所有的代工作，但无法弄清楚如何调用该可执行文件（codeGEN）库建成之前。我在Linux环境。希望有人能回答这个问题。

I am using CMake to build my C++ project and it has multiple executables and a library (all part of same project). All is working fine, however one of my executables is a code generator that creates some of the library classes. I have got all the generation working but can't figure out how to call this executable (codegen) just before the library is built. I am on Linux environment. Hope someone can answer this.

推荐答案

在的CMakeLists.txt ：

首先，定义你的可执行文件：

First, define your executable:

add_executable(marks-code-generator gen.cpp)

然后，定义自定义命令生成源：

Then, define a custom command to generate the source:

add_custom_command(OUTPUT generated.cpp generated.hpp
                   COMMAND marks-code-generator ARGS args here maybe
                   MAIN_DEPENDENCY input-file.in
                   DEPENDS marks-code-generator
                   COMMENT here we go!
                   VERBATIM)

选项逐字确保特定平台的转义正确。在注释将被打印出来让执行时，给像 [66％]在这里，我们走！。

The option VERBATIM makes sure platform-specific escaping is done correctly. The COMMENT will be printed out as make executes, giving something like [ 66%] here we go!.

最后，命名源列表中生成的源代码为您实际的程序：

Finally, name your generated source in the source list for your real program:

add_executable(some-program generated.cpp generated.hpp non-generated.cpp foo.cpp)

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