程序不等待与scanf的用户输入（＆QUOT;％C＆QUOT;，＆安培; YN）; [英] Program doesn't wait for user input with scanf("%c",&yn);

问题描述

这是基本的code到一个程序我写使用文件C.我想检测输出文件是否已经存在，如果练它确实存在我想询问用户是否愿意覆盖与否。这是我第一次有同的fopen（outfilename，R）打开了outfilename文件的原因;而不是给fopen（outfilename，W）;

据检测然而，文件的情况下不存在，如果它存在执行（输出文件已经存在，覆盖（Y / N））的printf的;语句，但完全忽略了scanf函数（％C，＆安培; YN）;声明！

在程序结束时的printf写着YN = 0如果文件不存在，只是YN =如果它确实存在。任何人可以帮助我吗？

 的#include＆LT;＆stdio.h中GT;
＃包括LT＆;＆stdlib.h中GT;
＃包括LT＆;＆FLOAT.H GT;
＃包括LT＆;＆string.h中GT;诠释主要（无效）{
    FILE * INF;
    FILE * OUTF;
    字符文件名[21]，outfilename [21];
    焦炭YN ='0';    的printf（请输入输入文件名：）;
    scanf函数（％S，＆安培;文件名）;    的printf（请输入一个输出文件名：）;
    scanf函数（％S，＆安培; outfilename）;    / *读取*打开文件/
    INF = FOPEN（文件名，R）;
    OUTF = FOPEN（outfilename，R）;    / *检查输入文件是否存在* /
    如果（INF！= NULL）{        / *检查输出文件不存在* /
        如果（OUTF == NULL）{
            FCLOSE（OUTF）;
            / *如果它不存在于写模式*通过打开文件/
            OUTF =的fopen（outfilename，W）;
        }其他{
            / *如果文件确实存在，给覆盖或不是选项* /
            输出（输出文件已经存在，覆盖（Y / N）：）;
            scanf函数（％C，＆安培; YN）;
        }
    }
    的printf（\\ n YN =％C \\ N，YN）;
    返回0;
}
 

解决方案

 的printf（请输入一个输出文件名：）;
scanf函数（％S，＆安培; outfilename）;
 

当你进入第二个字符串，然后按Enter键，一个字符串的字符被放置在输入缓冲区中，他们分别是：输入的字符串和换行符character.The字符串获取由 scanf的但换行保持在输入缓冲器

另外，

  scanf函数（％C，＆安培; YN）;
 

您接下来的 scanf函数读取字符只是读取/消耗换行符，因此从不等待用户输入。

解决方案是消耗使用额外的换行符：

  scanf函数（％C，＆安培; YN）;
      ^^^＆LT; ------------注意空间
 

或使用的getchar（）

您可能想看看我的答案 这里 作为一步解释详细的一步的问题。

This is the basic code to a program I am writing to practise using files in C. I am trying to detect whether the output file already exists and if it does exist I want to ask the user if they would like to overwrite it or not. This is the reason that I have first opened the outfilename file in with fopen(outfilename,"r"); as opposed to fopen(outfilename,"w");.

It detects the case of the file not existing, however, if it does exist it executes the printf("Output file already exists, overwrite (y/n):"); statement but completely ignores the scanf("%c",&yn); statement!

The printf at the end of the program reads "yn=0" if the file doesn't exist and just "yn=" if it does exist. Can anybody help me?

#include <stdio.h>
#include <stdlib.h>
#include <float.h>
#include <string.h>

int main(void) {
    FILE *inf;
    FILE *outf;
    char filename[21],outfilename[21];
    char yn='0';

    printf("Please enter an input filename: ");
    scanf("%s",&filename);

    printf("Please enter an output filename: ");    
    scanf("%s",&outfilename);

    /* Open file for reading */
    inf=fopen (filename,"r");
    outf=fopen(outfilename,"r");

    /*check that input file exists*/
    if (inf!=NULL) {

        /*check that the output file doesn't already exist*/
        if (outf==NULL){
            fclose(outf);
            /*if it doesn't already exist create file by opening in "write" mode*/
            outf=fopen(outfilename,"w");
        } else {
            /*If the file does exist, give the option to overwrite or not*/
            printf("Output file already exists, overwrite (y/n):");
            scanf("%c",&yn);
        }
    }
    printf("\n yn=%c \n",yn);
    return 0;
}

解决方案

printf("Please enter an output filename: ");    
scanf("%s",&outfilename);

When you enter the second string and hit the ENTER key, a string and a character are placed in the input buffer, they are namely: the entered string and the newline character.The string gets consumed by the scanf but the newline remains in the input buffer.

Further,

scanf("%c",&yn);

Your next scanf for reading the character just reads/consumes the newline and hence never waits for user input.

Solution is to consume the extra newline by using:

scanf(" %c", &yn);
      ^^^   <------------Note the space

Or by using getchar()

You may want to check out my answer here for a detailed step by step explanation of the problem.

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