如何＆QUOT;而（* S ++ = * T ++）QUOT;复制一个字符串？ [英] How does "while(*s++ = *t++)" copy a string?

问题描述

我的问题是，这是什么code做的（由<一个href=\"http://www.joelonsoftware.com/articles/CollegeAdvice.html\">http://www.joelonsoftware.com/articles/CollegeAdvice.html):

My question is, what does this code do (from http://www.joelonsoftware.com/articles/CollegeAdvice.html):

while (*s++ = *t++);

该网站说，code以上副本的字符串，但我不明白为什么...

the website says that the code above copies a string but I don't understand why...

它有指针呢？

推荐答案

这是等同于这样的：

while (*t) {
    *s = *t;
    s++;
    t++;
}
*s = *t;

当了炭牛逼指的是'\\ 0'，while循环将终止。在此之前，它会复制 T 指向的字符是取值指向，然后增加焦炭取值和 T 来指向他们的阵列中的下一个字符。

When the char that t points to is '\0', the while loop will terminate. Until then, it will copy the char that t is pointing to to the char that s is pointing to, then increment s and t to point to the next char in their arrays.

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