如何比较字符串中的＆QUOT;若＆QUOT;声明？ [英] How to compare strings in an "if" statement?

问题描述

我要测试，看看类型字符的变量可以用正常的字符串，如奶酪像比较比较：

I want to test and see if a variable of type "char" can compare with a regular string like "cheese" for a comparison like:

#include <stdio.h>

int main()
{
    char favoriteDairyProduct[30];

    scanf("%s",favoriteDairyProduct);

    if(favoriteDairyProduct == "cheese")
    {
        printf("You like cheese too!");
    }
    else
    {
        printf("I like cheese more.");
    }

    return 0;
}

（我真正想要做的是比这更长的时间，但是这是我卡上的主要部分。）
因此，如何将一个是C比较两个字符串？

(What I actually want to do is much longer than this but this is the main part I'm stuck on.) So how would one compare two strings in C?

推荐答案

您正在寻找的功能 STRCMP 或 STRNCMP 从文件string.h 。

You're looking for the function strcmp, or strncmp from string.h.

由于字符串数组只是，你需要每个字符比较，所以这个功能会为你做的：

Since strings are just arrays, you need to compare each character, so this function will do that for you:

if (strcmp(favoriteDairyProduct, "cheese") == 0)
{
    printf("You like cheese too!");
}
else
{
    printf("I like cheese more.");
}

延伸阅读： STRCMP在cplusplus.com

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