读一个字符串与sscanf的空间 [英] reading a string with spaces with sscanf

问题描述

有关的一个项目，我想读一个int和一个字符串的字符串。唯一的问题是sscanf的出现打破读取％S当它看到的空间。反正有绕过这个限制？这里是什么我试图做一个例子：

For a project I'm trying to read an int and a string from a string. The only problem is sscanf appears to break reading an %s when it sees a space. Is there anyway to get around this limitation? Here's an example of what I'm trying to do:

#include<stdio.h>
#include<stdlib.h>

int main(int argc, char** argv) {
    int age;
    char* buffer;
    buffer = malloc(200 * sizeof(char));
    sscanf("19 cool kid", "%d %s", &age, buffer);

    printf("%s is %d years old\n", buffer, age);
    return 0;
}

什么它打印的是：酷是19岁我需要酷小子是19岁。有谁知道如何解决这一问题？

What it prints is: "cool is 19 years old" where I need "cool kid is 19 years old". Does anyone know how to fix this?

推荐答案

下面一行将开始阅读一些（％d个），其次是任何东西，从制表符，换行符不同（％[^ \\ t \\ n] ）。

The following line will start reading a number (%d) followed by anything different from tabs or newlines (%[^\t\n]).

sscanf("19 cool kid", "%d %[^\t\n]", &age, buffer);

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