静态编译Python的跨preTER？ [英] Compile the Python interpreter statically?
问题描述
我建立嵌入式Python间preTER一个特殊用途，并希望避免在动态库的依赖关系，所以我想编译间preTER用，而不是静态库（如文件libc.a 不是 libc.so ）。
I'm building a special-purpose embedded Python interpreter and want to avoid having dependencies on dynamic libraries so I want to compile the interpreter with static libraries instead (e.g. libc.a not libc.so).
我也想静态链接是Python标准库的一部分，所有动态库。我知道这是可以做到用 Freeze.py ，但有一个替代，以便它可以在一个步骤中完成？
I would also like to statically link all dynamic libraries that are part of the Python standard library. I know this can be done using Freeze.py, but is there an alternative so that it can be done in one step?
推荐答案
我发现这个（主要是关于Python模块静态编译）：
I found this (mainly concerning static compilation of Python modules):
表示所使用的位于此处的配置文件：
Which describes a file used for configuration located here:
<Python_Source>/Modules/Setup
如果没有present，它可以通过复制创建这个文件：
If this file isn't present, it can be created by copying:
<Python_Source>/Modules/Setup.dist
的设置文件具有万吨文档中它和 README 包含在源代码提供了很多很好的编译信息也是如此。
The Setup file has tons of documentation in it and the README included with the source offers lots of good compilation information as well.
我没试过编译，但是我觉得这些资源，我应该是成功的，当我尝试。我会后我的结果如下评论。
I haven't tried compiling yet, but I think with these resources, I should be successful when I try. I will post my results as a comment here.
要得到一个纯静态的Python可执行文件，还必须配置如下：
To get a pure-static python executable, you must also configure as follows:
./configure LDFLAGS="-static -static-libgcc" CPPFLAGS="-static"
一旦你用这些标志启用后，你可能会得到很多的警告有关重命名，因为库不是present。这意味着你没有配置模块/设置正确，需要：
A）添加一行（靠近顶部）是这样的：
a) add a single line (near the top) like this:
*static*
（这是星/星单词静态和星号无空格）
(that's asterisk/star the word "static" and asterisk with no spaces)
二）要提供静态的注释去掉所有模块（如数学，数组，等...）
b) uncomment all modules that you want to be available statically (such as math, array, etc...)
您可能还需要添加特定的连接器选项（如我上面贴的链接提到的）。我的经验，到目前为止一直认为库无需修改工作。
You may also need to add specific linker flags (as mentioned in the link I posted above). My experience so far has been that the libraries are working without modification.
它也可能是有益的运行使用如下：
It may also be helpful to run make with as follows:
make 2>&1 | grep 'renaming'
这将表明，没有能够编译所有模块由于被静态链接。
This will show all modules that are failing to compile due to being statically linked.
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