如果语句不工作? [英] If statements not working?

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本文介绍了如果语句不工作?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在编程小白。我只是想问问有什么不妥以下code:

I am a noob at programming. I just wanted to ask what is wrong with the following code:

scanf("%i", &battlechoice);

printf("BCHOICE WAS:%i\n", battlechoice);

if (battlechoice=4) //fleeing
{
    fleechance=rand() % 100;
    if (fleechance <= 49)
    {
        printf("You attempt to flee...\n");
        sleep(2000);
        printf("Oh dear! You failed to flee! Gamover!\n");
        printf("Thank you for playing! -Anthony\n");
        sleep(7000);
        exit(0);
    } 
    else
    {
        printf("You succeeded in fleeing! You will be returned to town\nshortly...\n\n\n\n\n");
        sleep(3000);
        break;
    }
}        //end fleeing

else if (battlechoice=1) //attacking
{
    //player damage gen
    printf("You commence the attack...\n");
    sleep(750);
    damagemax = rand() % lvl * 1.4;

    damageoutcome = damagemax + damagemin;
}

正在发生的事情是,它是做双方的if语句,尽管它们都具有不同的条件?哪里不对?先谢谢了。

What is happening is that it is doing both of the if statements, even though they both have different conditions? What is wrong? Thanks in advance.

推荐答案

你混淆赋值运算符 = 与等于运算符 == 。而不是这样写:

You're confusing the assignment operator = with the equals operator ==. Write this instead:

if (battlechoice == 4)

等。

某些C程序员使用尤达条件句,以避免无意中在这些情况下使用分配:

Some C programmers use "Yoda conditionals" to avoid accidentally using assignment in these cases:

if (4 == battlechoice)

例如,这将不能编译,捕捉错误:

For example this won't compile, catching the mistake:

if (4 = battlechoice)

这篇关于如果语句不工作?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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