通过引用在C传递指针参数？ [英] Passing pointer argument by reference under C?

问题描述

#include <stdio.h>
#include <stdlib.h>

void
getstr(char *&retstr)
{
 char *tmp = (char *)malloc(25);
 strcpy(tmp, "hello,world");
 retstr = tmp;
}

int
main(void)
{
 char *retstr;

 getstr(retstr);
 printf("%s\n", retstr);

 return 0;
}

GCC 不会编译该文件，但添加后的#include＆LT; CString的＆GT; 我可以用G ++来编译这个源文件。

gcc would not compile this file, but after adding #include <cstring> I could use g++ to compile this source file.

问题是：做C编程语言支持通过引用传递指针参数？如果不是，为什么？

The problem is: does the C programming language support passing pointer argument by reference? If not, why?

感谢。

推荐答案

没有，C不支持引用。这是由设计。相反，引用您可以使用指针C.引用指针只在C ++语言的版本。

No, C doesn't support references. It is by design. Instead of references you could use pointer to pointer in C. References are available only in C++ language.

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