区分大小写的字符串补偿用C [英] Case Insensitive String comp in C

问题描述

我有两个交codeS 的char * ，我想比较，忽略大小写。
是否有一个函数来做到这一点？

I have two postcodes char* that I want to compare, ignoring case. Is there a function to do this?

还是我通过每个必须循环使用tolower的功能，然后做比较呢？

Or do I have to loop through each use the tolower function and then do the comparison?

不知道如何该功能将与数字字符串中的反应

Any idea how this function will react with numbers in the string

感谢

推荐答案

有没有的功能，这是否在C标准。与POSIX符合Unix系统都要求有<一个href=\"http://pubs.opengroup.org/onlinepubs/9699919799/functions/strcasecmp.html\"><$c$c>strcasecmp在头 strings.h ;微软系统有 stricmp 。为了在便携式侧，写你自己的：

There is no function that does this in the C standard. Unix systems that comply with POSIX are required to have strcasecmp in the header strings.h; Microsoft systems have stricmp. To be on the portable side, write your own:

int strcicmp(char const *a, char const *b)
{
    for (;; a++, b++) {
        int d = tolower(*a) - tolower(*b);
        if (d != 0 || !*a)
            return d;
    }
}

但要注意，这些解决方案将使用UTF-8字符串，只有那些ASCII工作。

But note that none of these solutions will work with UTF-8 strings, only ASCII ones.

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