默认情况下，在开关状态 [英] Default case in a switch condition

问题描述

我有这样的code：

  #include<stdio.h>                                   
  int main()
  {   
      int a=10;
      switch(a)
      {   
      case '1':
          printf("ONE\n");
          break;
      case '2':
          printf("TWO\n");
          break;
      defalut:
          printf("NONE\n");
      }   
      return 0;
  }

程序不显示任何信息，甚至没有无。我想通了，默认有一个错字 defalut ！结果
我想知道为什么不被编译器检测到该语法错误。

The program doesn't print anything, not even NONE. I figured out that default had a typo defalut!
I want to know why this syntax error is not detected by the compiler.

推荐答案

defalut 仅仅是在你的程序的标签，你可以跳转到与转到。具有突出的关键字编辑会犯这样的错误更容易被发现。

defalut is just a label in your program that you can jump to with goto. Having an editor that highlights keywords could have made this error easier to spot.

我也应该注意到，你的程序可能有一些逻辑错误。字符 1 是不一样的 1 ，并用'一样2 和 2 。

I should also note that your program may have some logic errors. The character '1' is not the same as 1, and the same with '2' and 2.

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