是否有可能找到分配给指针的内存,而无需搜索malloc的声明 [英] Is it possible to find the Memory Allocated to the Pointer, without searching for the malloc statement
问题描述
假设我在一个函数分配的内存指针的一些富
:
Suppose I have allocated memory to some pointer in a function foo
:
void foo()
{
// ...
int *ptr = malloc(20*sizeof(int));
bar (ptr);
}
从富()
,我通过这个指针巴()
键,比方说从巴()
给其他功能。
From foo()
, I pass this pointer to bar()
and let's say from bar()
to another function.
现在,在一定的时间点,我要检查:多少内存分配给指针
Now, at some point of time, I want to check: How much memory was allocated to the pointer.
是否有任何可能的方式,无需搜索的语句:
Is there any possible way, without searching for the statement:
int *ptr = malloc(20*sizeof(int));
要找出多少内存分配给指针,使用GDB?
to figure out how much memory is allocated to the pointer, using GDB?
感谢。
推荐答案
答案是:它的依赖的
很多系统提供 MSIZE()
[1], malloc_usable_size()
[2],或类似的功能。如果你是这样的系统上,(GDB)打印malloc_usable_size(PTR)
是你所需要的。
Many systems provide msize()
[1], malloc_usable_size()
[2], or similar function. If you are on such a system, (gdb) print malloc_usable_size(ptr)
is all you need.
[1] <一个href=\"http://msdn.microsoft.com/en-us/library/z2s077bc(v=vs.80).aspx\">http://msdn.microsoft.com/en-us/library/z2s077bc(v=vs.80).aspx
[2] <一个href=\"http://www.slac.stanford.edu/comp/unix/package/rtems/doc/html/libc/libc.info.malloc.html\">http://www.slac.stanford.edu/comp/unix/package/rtems/doc/html/libc/libc.info.malloc.html
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