如何处理realloc的由于内存时失败？ [英] How to handle realloc when it fails due to memory?

问题描述

问题说，这一切，但这里有一个例子：

Question says it all but here is an example:

typedef struct mutable_t{
    int count, max;
    void **data;
} mutable_t;


void pushMutable(mutable_t *m, void *object)
{
    if(m->count == m->max){
        m->max *= 2;
        m->data = realloc(m->data, m->max * sizeof(void*));
    }
    // how to handle oom??
    m->data[m->count++] = object;
}

我

该如何处理运行内存和NOT NULL所有我的数据？

How can I handle running out of memory and not NULL out all of my data?

编辑 - 假设有东西可以做如释放一些内存的地方，或者至少告诉用户：你不能这样做 - 你是内存不足。理想情况下，我想留下什么被分配在那里。

edit - let's assume there is something which could be done e.g. free up some memory somewhere or at least tell the user "you can't do that - you're out of memory". Ideally I would like to leave what was allocated there.

推荐答案

标准的方法是引入新的变量来保存从realloc的回报。那么你只覆盖您的输入变量，如果它成功了：

The standard technique is to introduce a new variable to hold the return from realloc. You then only overwrite your input variable if it succeeds:

tmp = realloc(orig, newsize);
if (tmp == NULL)
{
    // could not realloc, but orig still valid
}
else
{
    orig = tmp;
}

这篇关于如何处理realloc的由于内存时失败？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！