为const char *级联 [英] const char* concatenation

问题描述

我需要连接两个字符常量像这样的：

I need to concatenate two const chars like these:

const char *one = "Hello ";
const char *two = "World";

我怎么会去这样做？

How might I go about doing that?

我通过了这些的char * 期从第三方库，C接口，所以我不能简单地使用的std ::字符串代替。

I am passed these char*s from a third-party library with a C interface so I can't simply use std::string instead.

推荐答案

在您的例子的有一个的和的两个的是字符指针，指向char的常量。你不能改变这些指针指向的字符常量。因此，任何类似：

In your example one and two are char pointers, pointing to char constants. You cannot change the char constants pointed to by these pointers. So anything like:

strcat(one,two); // append string two to string one.

将不起作用。相反，你应该有一个单独的变量（字符数组）来保存结果。事情是这样的：

will not work. Instead you should have a separate variable(char array) to hold the result. Something like this:

char result[100];   // array to hold the result.

strcpy(result,one); // copy string one into the result.
strcat(result,two); // append string two to the result.

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