正则表达式来拔出C函数原型声明？ [英] Regex to pull out C function prototype declarations?

问题描述

我在什么地方学习曲线，当涉及到普通EX pressions，我需要用它们来自动修改函数原型在一堆C头文件。有谁知道一个像样的正规前pression找到在C头的任何和所有函数原型，而排除其他一切？

编辑：三件事情并没有初步明确：

1. 我不关心C ++中，只有直C.这意味着没有模板等可担心的。


2. 解决方案必须以typedef和结构，不局限于只有基本的C类型的工作。


3. 这是一种一次性的事情。它并不需要是pretty。我不在乎多少杂牌它，只要它的作品，但我不想要一个复杂的，难以实施的解决方案。

解决方案

您可以实现使用解析器的 ANSI C的yacc /法语法。

I'm somewhere on the learning curve when it comes to regular expressions, and I need to use them to automatically modify function prototypes in a bunch of C headers. Does anyone know of a decent regular expression to find any and all function prototypes in a C header, while excluding everything else?

Edit: Three things that weren't clear initially:

1. I do not care about C++, only straight C. This means no templates, etc. to worry about.
2. The solution must work with typedefs and structs, no limiting to only basic C types.
3. This is kind of a one-off thing. It does not need to be pretty. I do not care how much of a kludge it is as long as it works, but I don't want a complex, hard to implement solution.

解决方案

You may implement a parser using ANSI C yacc/lex grammar.

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