C:printf的浮点值 [英] C: printf a float value
问题描述
我要打印的有2个整数位和逗号之后是6位小数浮点值。如果我只是用的printf(%F,myFloat)
我得到一个截断的值。
I want to print a float value which has 2 integer digits and 6 decimal digits after the comma. If I just use printf("%f", myFloat)
I'm getting a truncated value.
我不知道这是否总是用C发生,也只是因为我使用C微控制器(CCS是精确的)是,但在引用它告诉%F
得到这一点:截断浮动
I don't know if this always happens in C, or it's just because I'm using C for microcontrollers (CCS to be exact), but at the reference it tells that %f
get just that: a truncated float.
如果我的持股量 44.556677
,我打印出44.55
,只有前两个小数位数
If my float is 44.556677
, I'm printing out "44.55"
, only the first two decimal digits.
所以,问题是...我怎样才能打印我的6位数字(和他们的只是六,以防万一我有以后什么零)?
So the question is... how can I print my 6 digits (and just the six of them, just in case I'm having zeros after that or something)?
推荐答案
您可以做到这一点是这样的:
You can do it like this:
printf("%.6f", myFloat);
6重$ P $点后psents的位数。
6 represents the number of digits after the dot.
P.S。感谢@caf指正。
P.S. Thanks @caf for correcting me.
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