是什么difftime和之间的差值“ - ”? [英] what is the difference between difftime and '-'?
问题描述
我有time_t类型的2个变量 - varEnd和varStart。
现在,为了看它们之间的区别
要么我可以做
I have 2 variables of type time_t - varEnd and varStart. Now in order to see the difference between them Either I can do
varEnd - varStart;
或
difftime(varEnd, varStart);
和两个返回的秒数。
请让我知道,如果他们有什么区别吗?或者是推荐一个?
Please let me know, if they have any difference? or which is the recommended one?
推荐答案
语言指定 time_t的
能够重新presenting倍的算术类型。它不要求它重新present时间以任何具体方式。
The language specifies that time_t
is an arithmetic type capable of representing times. It doesn't require it to represent times in any particular way.
如果 time_t的
重新presents时间,因为某些时刻的秒数,在 -
运营商将正确计算两个 time_t的
值之间以秒为单位的差异。
If time_t
represents time as the number of seconds since some moment, the -
operator will correctly compute the difference in seconds between two time_t
values.
如果它没有(比方说,如果粒度是一毫秒,或者如果一个 time_t的
被分成组重新presenting年,月的位,天等),那么 -
运营商可以产生无意义的结果。
If it doesn't (say, if the granularity is one millisecond, or if the bits of a time_t
are divided into groups representing years, months, days, etc.), then the -
operator can yield meaningless results.
difftime()
一>功能,而另一方面,知道如何 time_t的
重新presents时间,并使用该信息来计算秒的差异。
The difftime()
function, on the other hand, "knows" how a time_t
represents a time, and uses that information to compute the difference in seconds.
在大多数的实现,简单的减法和 difftime()
碰巧做同样的事情 - 但只有 difftime()
是保证在正常工作的所有的实现。
On most implementations, simple subtraction and difftime()
happen to do the same thing -- but only difftime()
is guaranteed to work correctly on all implementations.
另一个区别: difftime()
返回浮点型的结果双击
,而 -
在 time_t的
值类型产生的结果 time_t的
。在大多数情况下,结果将被隐式转换到任何你把它分配到的类型,但是,如果 time_t的
恰好是一个无符号整数类型,从稍后的时间减法较早的时间将产生一个非常大的值,而不是一个负值。每个系统我见过的农具 time_t的
为32位或64位有符号整数类型,但使用一个无符号类型猫 - 一个原因是简单的减法 time_t的
值是没有必要的意义。
Another difference: difftime()
returns a result of the floating-point type double
, while "-"
on time_t
values yields a result of type time_t
. In most cases the result will be implicitly converted to the type of whatever you assign it to, but if time_t
happens to be an unsigned integer type, subtraction of a later time from an earlier time will yield a very large value rather than a negative value. Every system I've seen implements time_t
as a 32-bit or 64-bit signed integer type, but using an unsigned type is permitted -- one more reason that simple subtraction of time_t
values isn't necessary meaningful.
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