为什么我不能用这个code覆盖一个字符串？ [英] Why can't I use this code to overwrite a string?

问题描述

code

#include "stdio.h"
#include "string.h"

int main()
{
  char *p = "abc";
  printf("p is %s \n", p);
  return 0;
}

输出

p is abc

---

code

#include "stdio.h"
#include "string.h"

int main()
{
  char *p = "abc";
  strcpy(p, "def");
  printf("p is %s \n",p);
  return 0;
}

输出

Segmentation fault (core dumped)

有人能解释为什么出现这种情况？

Could someone explain why this happens?

推荐答案

在您的code：

char *p="abc";

p指向字符串文本 - 你不能改变字符串文字，这是你对strcpy的呼叫尝试做的。相反，使P上数组：

p points to a string literal - you are not allowed to change string literals, which is what your call to strcpy is trying to do. Instead, make p an array:

char p[] = "abc";

这将文字复制到的东西，你被允许修改。

which will copy the literal into something that you are allowed to modify.

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