试图用C访问Twitter流API [英] Trying to Access Twitter Streaming API with C

问题描述

我从Ç的libcurl的code获取输出到一个字符串。我修改了它，我想用它来访问Twitter的数据流。我加了 curl_easy_setopt（卷曲，CURLOPT_URL，http://stream.twitter.com/1/statuses/sample.json）; 和 curl_easy_setopt （卷曲，CURLOPT_USERPWD，neilmarion：MY_PASSWORD）; 在code。但问题是，每当我执行它，没有输出。要做就要做到什么问题？谢谢你。

 的#include＆LT;＆stdio.h中GT;
＃包括LT＆;＆stdlib.h中GT;
＃包括LT＆;＆string.h中GT;
＃包括LT＆;卷曲/ curl.h＆GT;结构串{
  字符* PTR;
  为size_t LEN;
};无效init_string（结构串* S）{
  S-GT＆; LEN = 0;
  S-GT＆; PTR =的malloc（S-GT＆; LEN + 1）;
  如果（S-GT＆; PTR == NULL）{
    fprintf中（标准错误的malloc（）失败\\ n）;
    出口（EXIT_FAILURE）;
  }
  S-GT＆; PTR [0] ='\\ 0';
}为size_t writefunc（无效* PTR，为size_t长度size_t nmemb个，结构串* S）
{
  为size_t new_len = S-＆GT; LEN +尺寸* nmemb个;
  S-GT＆; PTR =的realloc（S-GT＆; PTR，new_len + 1）;
  如果（S-GT＆; PTR == NULL）{
    fprintf中（标准错误，realloc（）的失败\\ n）;
    出口（EXIT_FAILURE）;
  }
  的memcpy（S-GT＆; PTR + S-＆GT; LEN，PTR，大小* nmemb个）;
  S-GT＆; PTR [new_len] ='\\ 0';
  S-GT＆; LEN = new_len;  返回大小* nmemb个;
}INT主要（无效）
{
  卷曲*卷曲;
  卷曲code资源;  卷曲= curl_easy_init（）;
  如果（卷曲）{
    结构字符串s;
    init_string（安培; S）;    curl_easy_setopt（卷曲，CURLOPT_URL，http://stream.twitter.com/1/statuses/sample.json）;
    curl_easy_setopt（卷曲，CURLOPT_USERPWD，neilmarion：MY_PASSWORD）;
    curl_easy_setopt（卷曲，CURLOPT_WRITEFUNCTION，writefunc）;
    curl_easy_setopt（卷曲，CURLOPT_WRITEDATA，＆安培; S）;
    RES = curl_easy_perform（卷曲）;    的printf（％S \\ n，s.ptr）;
    免费（s.ptr）;    / *总是清理* /
    curl_easy_cleanup（卷曲）;
  }
  返回0;
}
 

解决方案

最快的下一步可能是设置CURLOPT_HEADER，包括身体的输出头。最有可能的，我猜它是失败的安全性，你会看到在头部的细节。

I got the code from C libcurl get output into a string. I modified it and I want to use it to access the Twitter Stream. I added curl_easy_setopt(curl, CURLOPT_URL, "http://stream.twitter.com/1/statuses/sample.json"); and curl_easy_setopt(curl, CURLOPT_USERPWD, "neilmarion:my_password"); in the code. But the problem is whenever I execute it, there is no output. What must be the problem? Thanks.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <curl/curl.h>

struct string {
  char *ptr;
  size_t len;
};

void init_string(struct string *s) {
  s->len = 0;
  s->ptr = malloc(s->len+1);
  if (s->ptr == NULL) {
    fprintf(stderr, "malloc() failed\n");
    exit(EXIT_FAILURE);
  }
  s->ptr[0] = '\0';
}

size_t writefunc(void *ptr, size_t size, size_t nmemb, struct string *s)
{
  size_t new_len = s->len + size*nmemb;
  s->ptr = realloc(s->ptr, new_len+1);
  if (s->ptr == NULL) {
    fprintf(stderr, "realloc() failed\n");
    exit(EXIT_FAILURE);
  }
  memcpy(s->ptr+s->len, ptr, size*nmemb);
  s->ptr[new_len] = '\0';
  s->len = new_len;

  return size*nmemb;
}

int main(void)
{
  CURL *curl;
  CURLcode res;

  curl = curl_easy_init();
  if(curl) {
    struct string s;
    init_string(&s);

    curl_easy_setopt(curl, CURLOPT_URL, "http://stream.twitter.com/1/statuses/sample.json");
    curl_easy_setopt(curl, CURLOPT_USERPWD, "neilmarion:my_password");
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, writefunc);
    curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s);
    res = curl_easy_perform(curl);

    printf("%s\n", s.ptr);
    free(s.ptr);

    /* always cleanup */
    curl_easy_cleanup(curl);
  }
  return 0;
}

解决方案

The quickest next step is probably to set CURLOPT_HEADER, to include headers in the body output. Most likely, I would guess it is failing on security, and you'll see the details in the headers.

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