转换位字段为int [英] Converting Bit Field to int

问题描述

我有位域声明是这样的：

I have bit field declared this way:

typedef struct morder {
    unsigned int targetRegister : 3;
    unsigned int targetMethodOfAddressing : 3;
    unsigned int originRegister : 3;
    unsigned int originMethodOfAddressing : 3;
    unsigned int oCode : 4;
} bitset;

我也有int数组，我想从这个数组得到int值时，重新presents该位字段的实际值（实际上是某种机器字的，我有它的部分，我希望整个字的INT再presentation）。

I also have int array, and i want to get int value from this array, that represents the actual value of this bit field (which is actually some kind of machine word that i have the parts of it, and i want the int representation of the whole word).

非常感谢。

推荐答案

您可以使用一个联盟：

typedef union bitsetConvertor {
    bitset bs;
    uint16_t i;
} bitsetConvertor;

bitsetConvertor convertor;
convertor.i = myInt;
bitset bs = convertor.bs;

或者你可以使用一个转换：

Or you can use a cast:

bitset bs = *(bitset *)&myInt;

您也可以在联盟内使用匿名结构：

Or you can use an anonymous struct within a union:

typedef union morder {
    struct {
        unsigned int targetRegister : 3;
        unsigned int targetMethodOfAddressing : 3;
        unsigned int originRegister : 3;
        unsigned int originMethodOfAddressing : 3;
        unsigned int oCode : 4;
    };

    uint16_t intRepresentation;
} bitset;

bitset bs;
bs.intRepresentation = myInt;

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