如何隐藏在printf的前导零 [英] How to hide leading zero in printf

问题描述

以下输出 0.23 。我如何得到它简单地输出 0.23 ？

 的printf（％8.2f0.23）;
 

解决方案

C标准说，为˚F和˚F浮点格式说明：

  

如果出现小数点字符，至少有一个数字出现之前。

我认为，如果你不想零到小数点前出现，你可能必须做一些像使用的snprintf（）来格式化数字转换成字符串，并删除 0 如果格式化字符串开头0。 （以及类似地为-0）。然后传递格式化字符串我们的实际产出。或者类似的东西。

The following outputs 0.23. How do I get it to simply output .23?

printf( "%8.2f" , .23 );

解决方案

The C standard says that for the f and F floating point format specifiers:

If a decimal-point character appears, at least one digit appears before it.

I think that if you don't want a zero to appear before the decimal point, you'll probably have to do something like use snprintf() to format the number into a string, and remove the 0 if the formatted string starts with "0." (and similarly for "-0."). Then pass that formatted string to our real output. Or something like that.

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