GCC编译错误：施放指定数组类型 [英] gcc compile error: cast specifies array type

问题描述

以下code是完美有效，

The following code is perfect valid,

int *ia = (int[]){1,3,5,7};

但是当我编译code的下一行，

but when I compile the next line of code,

char *p = (char[]) "abc";

GCC说

test.c:87: error: cast specifies array type

看来它们以相同的方式流延。没有第二个，为什么得到一个错误信息？

It seems they are casted in the same way. Why did the second one get an err msg?

正如你们所说，ABC是一个指针，它不能转换为一个指针。因此，我的另一个问题：为什么

As you guys said, "abc" is a pointer, which cannot be converted to be a pointer. So my another question: why does

 char[] s = "abc";

是有效的。如何code的工作上面的行编译时？

is valid. How does the above line of code work when compiling?

推荐答案

这是有效的，因为在右侧的前pression是C99的复合文字的，不是施法：

This is valid because the expression on the right hand side is a C99 compound literal, not a cast:

int *ia = (int[]){1,3,5,7};

然而，这是因为它是一个的铸前pression 的，而不是字面化合物是无效的。由于GCC告诉你，你不能转换为数组类型：

However, this is not valid because it is a cast-expression, not a compound literal. As GCC is telling you, you can't cast to array types:

char *p = (char[]) "abc";

您可以通过使适当的复合文字修复它 - 他们是由括号表示：

You can fix it by making it a proper compound literal - they are denoted by the braces:

char *p = (char[]){"abc"};

这篇关于GCC编译错误：施放指定数组类型的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！