而重新套接字绑定错误 [英] Bind error while recreating socket

问题描述

一个有以下监听套接字：

A have the following listener socket:

int sd = socket(PF_INET, SOCK_STREAM, 0);

struct sockaddr_in addr;
bzero(&addr, sizeof(addr));
addr.sin_family = AF_INET;
addr.sin_port = htons(http_port);
addr.sin_addr.s_addr = INADDR_ANY;

if(bind(sd,(sockaddr*)&addr,sizeof(addr))!=0)
{
    ...
}

if (listen(sd, 16)!=0)
{
    ...
}

int sent = 0;
for(;;) {
    int client = accept(sd, (sockaddr*)&addr, (socklen_t*)&size);
    if (client > 0)
    {
        ...
        close(client);
    }
}

如果一个用

close(sd);

，然后试图重新插座相同code，A绑定错误发生，30〜60秒一个新的socket创建成功后才能。

and then trying to recreate socket with the same code, a bind error happens, and only after 30-60 second a new socket is created successfully.

这有什么办法可以创建或接近一些很酷的方式，以避免绑定错误？

It there a way to create or close in some cool way to avoid bind error?

推荐答案

某处在内核中，还是有你的previous插座周围挂着一些信息。告诉你愿意内核反正重新使用的端口：

Somewhere in the kernel, there's still some information about your previous socket hanging around. Tell the kernel that you are willing to re-use the port anyway:

int yes=1;
//char yes='1'; // use this under Solaris

if (setsockopt(sockfd, SOL_SOCKET, SO_REUSEADDR, &yes, sizeof(yes)) == -1) {
    perror("setsockopt");
    exit(1);
}

请参阅 beej说明书中的bind（）的部分网络编程更详细的解释。

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