如何打印出破折号或使用fprintf中/ printf的点？ [英] How to print out dash or dot using fprintf/printf?

问题描述

截至现在，我使用下面一行与出点的打印

As of now I'm using below line to print with out dot's

fprintf( stdout, "%-40s[%d]", tag, data);

我期待的输出会像下面，

I'm expecting the output would be something like following,

Number of cards..................................[500]
Fixed prize amount [in whole dollars]............[10]
Is this a high winner prize?.....................[yes]

如何使用fprintf中/ printf的打印出破折号或点？

How to print out dash or dot using fprintf/printf?

推荐答案

一个更快的方法：

如果你永远需要预先知道填充的最大数量（这通常是当你像格式化你有一个固定宽度表的情况下），你可以使用一个静态的轧车字符串，只要抓住一大块出来。这将是比调用的printf 或 COUT 在一个循环更快。

If the maximum amount of padding that you'll ever need is known in advance (which is normally the case when you're formatting a fixed-width table like the one you have), you can use a static "padder" string and just grab a chunk out of it. This will be faster than calling printf or cout in a loop.

static const char padder[] = "......................"; // Many chars

size_t title_len = strlen(title);
size_t pad_amount = sizeof(padder) - 1 - title_len;

printf(title); // Output title

if (pad_amount > 0) {
    printf(padder + title_len); // Chop!
}

printf("[%d]", data);

您甚至可以做到在一个声明中，有信念的跨越：

You could even do it in one statement, with some leap of faith:

printf("%s%s[%d]", title, padder + strlen(title), data);

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