转换一个UINT32值转换成数组UINT8 [4] [英] Converting a UINT32 value into a UINT8 array[4]

问题描述

我的问题是你如何pferably独立字节序的方式UINT32值转换为UINT8数组[4]（C / C ++）$ P $？此外，你将如何从UINT8阵列重建UINT32值[4]，要回你开始的地方？

My question is how do you convert a UINT32 value to a UINT8 array[4] (C/C++) preferably in a manner independent of endianness? Additionally, how would you reconstruct the UINT32 value from the UINT8 array[4], to get back to where you started?

推荐答案

例如。像这样的：

UINT32 value;
UINT8 result[4];

result[0] = (value & 0x000000ff);
result[1] = (value & 0x0000ff00) >> 8;
result[2] = (value & 0x00ff0000) >> 16;
result[3] = (value & 0xff000000) >> 24;

编辑：加括号（>>似乎有更高的precedence比＆安培;）

added parenthesis (>> seems to have higher precedence than &)

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